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Problem Answer

After writing and balancing the equation, the C4H10 : O2 molar ratio is 1 : 6.50. The correct answer is therefore 3.67 moles of oxygen.


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Calculate Stoichiometry Expression

Writing A Thermochemical Equation

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Background

  • Write a balanced equation for the combustion. This is a chapter 6 objective. Check textbook page 188 (Simple Combustion) for help with this step.
  • Consider the molar interpretation of this equation. For example, if the combustion of one mole of ethane (C2H6) produces 372 kilocalories, then the following thermochemical equation would be written:
    2 C2H6 + 7 O2 ---> 4 CO2 + 6 H2O  Q = -744 kcal
    The value 744 is 2X the 372 because the equation is balanced for 2 moles of C2H6.
  • Finally, notice that the direct proportional relationship between moles and energy is applicable to any reactant or product. For example, 1488 kilocalories (2X744) of energy would be produced if 14 (2X7) moles of O2 is consumed. Textbook Discussion: Sections 7.10 & 7.11, pages 227-232. See Also: Example IX, X, and XI, pages 228, 229, and 230.

Problem

The combustion of one mole of butane (C4H10) produces 690 kilocalories. Write the balanced equation for the combustion of butane. Based on this equation, how many moles of oxygen gas (O2) will be consumed when the combustion of a sufficient quantity of butane produces 390 kilocalories?

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